Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 7 - Work and Kinetic Energy - Problems and Conceptual Exercises - Page 212: 25

Answer

(a) $-10J$ (b) $0.63N$ upward

Work Step by Step

(a) We know that $W=Delta K.E$ $W=K.E_f-K.E_i$ $W=\frac{1}{2}mv_f^2-mgh$ $W=m(\frac{1}{2}v_f^2-gh)$ We plug in the known values to obtain: $W=(0.140)[\frac{1}{2}(13)^2-(9.81)(16)]$ $W=-10J$ (b) We know that $W=-Fd$ This can be rearranged as: $F=\frac{-W}{d}$ We plug in the known values to obtain: $F=\frac{-(-10)}{16}$ $F=0.63N$ upward
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