Answer
$0.67KN$
Work Step by Step
We can find the required tension as
$\Sigma F_y=T-W=ma_c$
$\implies T=W+ma_c$
$T=mg+\frac{mv^2}{r}$
$T=m(g+\frac{v^2}{r})$
We plug in the known values to obtain:
$T=(63)(9.81+\frac{(2.4)^2}{6.9})$
$T=0.67KN$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 6 - Applications of Newton's Laws - Problems and Conceptual Exercises - Page 183: 59
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
