Answer
(D) $4.21\times 10^4$ N
Work Step by Step
We know that
$a=\frac{v^2-v_{\circ}^2}{2s}$
We plug in the known values to obtain:
$a=\frac{(0m/s)^2-(36m/s)^2}{2(1m)}$
$a=-648m/s^2$
Now $F=(65Kg)(-648m/s^2)$
$F=-4.21\times 10^4N$
Thus, the magnitude of force on the driver is $4.21\times 10^4N$ and hence the correct option is $D$.