Answer
$102.8N$
Work Step by Step
We can find the required force as follows:
$F_1y=F_2y$
$\implies F_1sin\theta_1=F_2sin\theta_2$
We plug in the known values to obtain:
$Fsin45^{\circ}=130sin134^{\circ}$
This can be rearranged as:
$F=\frac{(130)(0.5592)}{0.7071}$
$F=102.8N$
