Answer
(a) Less than. (b) Choice III
Work Step by Step
Assume that the force of drag is proportional to velocity. This means that the net force is equal to weight minus drag, which would be $F=mg-kv$, where $k$ is a constant. The acceleration would be equal to $a=\frac{F}{m}=\frac{mg-kv}{m}=g-\frac{k}{m}v$. As mass increases, acceleration becomes larger and the drag force becomes less effective. Therefore, the time it takes for the Ball 1 to reach the ground will be less than the time for Ball 2.