Answer
$n=3$
$l=0$
$m_l=0$
$m_s=\frac{-1}{2}\space and \frac{+1}{2}$
Work Step by Step
We know that for the 3s subshell
$n=3$ and for the s subshell l=0
We also know that for $n=3$ and $l=0$ $m_l=0$ and $m_s=\frac{-1}{2}\space and \frac{+1}{2}$
Hence, the required set of four quantum numbers is:
$n=3$
$l=0$
$m_l=0$
$m_s=\frac{-1}{2}\space and \frac{+1}{2}$