Answer
$(\frac{n}{n+1})^2U$
Work Step by Step
We know that
$U_n=\frac{-KZe^2}{r_n}$
$\implies U_n\propto \frac{1}{r_n}$
As $r_n\propto n^2$
$\implies U_n\propto \frac{1}{n^2}$
We know that
$U_n\times n^2=constant$
Thus, $(U_{n+1})(n+1)^2=(U_n)(n^2)$
$\implies U_{n+1}=U_n[\frac{n^2}{(n+1)^2}]$
$\implies U_{n+1}=(\frac{n}{n+1})^2U$