Answer
7.53$\times 10^{-19}$ J
Work Step by Step
We know that
$W_{\circ}=\frac{hc}{\lambda}$
We plug in the known values to obtain:
$W_{\circ}=\frac{(6.63\times 10^{-34}J.s)(3\times 10^8m/s)}{264\times 10^3m}$
$W_{\circ}=7.53\times 10^{-19}J$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 30 - Quantum Physics - Problems and Conceptual Exercises - Page 1074: 28
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