Answer
(a) diverging
(b) converging
(c) distant object:$-0.2 diopters$; near object $2.0 diopters$
Work Step by Step
(a) We know that the diverging lens can produce an image of a distant object at the physician far point distance; therefore, the physician should wear glasses with diverging lenses.
(b) We know that a converging lens in front of the eye can correct farsightedness. The convex lens focuses light from an object inside the near point to produce an image that is beyond the near point and in this way the eye can focus on the image of the object.
(c) For distant objects
$\frac{1}{f}=\frac{1}{\infty}+\frac{1}{-5.0m}$
$\implies \frac{1}{f}=-0.2diopters$
and for the near point
$\frac{1}{f}=\frac{1}{0.25m}-\frac{1}{0.50m}$
$\implies \frac{1}{f}=2.0 diopters$
