Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 26 - Geometrical Optics - Problems and Conceptual Exercises - Page 941: 42

Answer

$92cm$

Work Step by Step

We know that $m=-\frac{d_i}{d_{\circ}}$ $\implies d_i=-md_{\circ}$ We plug in the known values to obtain: $d_i=-2.2\times 25cm=-55cm$ We also know that $\frac{1}{f}=\frac{1}{d_{\circ}}+\frac{1}{d_i}$ $\implies \frac{1}{f}=\frac{d_{\circ}d_i}{d_{\circ}+d_i}$ $\implies \frac{1}{f}=\frac{25\times (-55)}{25-55}cm$ $\frac{1}{f}=45.83cm$ Now we can find the required radius of curvature as $R=2f$ We plug in the known values to obtain: $R=2(45.83)$ $R=92cm$
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