Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 25 - Electromagnetic Waves - Problems and Conceptual Exercises - Page 904: 90

Answer

$\Delta x=9.0mm$

Work Step by Step

We can find the required uncertainty as follows: $\Delta x=c\Delta t$ We plug in the known values to obtain: $\Delta x=(3.00\times 10^8)(0.030\times 10^{-9})$ $\Delta x=9.0mm$
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