Answer
$I_{rms}=1.32A$
Work Step by Step
We know that
$X_c=\frac{1}{\omega C}$
We plug in the known values to obtain:
$X_c=\frac{1}{[2\pi (100)]105}=25.26\Omega$
Now we can find the rms current in the circuit as follows:
$I_{rms}=\frac{V_rms}{X}$
We plug in the known values to obtain:
$I_{rms}=\frac{20}{15.2}=1.32A$
