Answer
$1.1\mu V$
Work Step by Step
We know that
$\epsilon=(N)|\frac{\Delta \phi}{\Delta t}|$
$\epsilon=(N)|\frac{BA(cos90^{\circ}-cos^{\circ})}{\Delta t}|$
We plug in the known values to obtain:
$\epsilon=(85)|\frac{\pi(1.5\times 10^{-4})(0.0010)^2}{37\times 10^{-3}}|=1.1\mu V$