Answer
$64mT$
Work Step by Step
We know that
$B_{min}=\frac{mg}{2IL}$
We plug in the known values to obtain:
$B_{min}=\frac{(0.035Kg)(9.8m/s^2)}{2\times 18A\times 0.15m}$
$B_{min}=64\times 10^{-3}T=64mT$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 22 - Magnetism - Problems and Conceptual Exercises - Page 798: 105
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
