Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 21 - Electric Current and Direct-Current Circuits - Problems and Conceptual Exercises - Page 762: 125

Answer

$(A)~1.25\times 10^7~\Omega$

Work Step by Step

We can find the resistance of the person footwear as follows: $I=\frac{\mathcal{E}}{R+R_{pf}}$ Where $R_{pf}$ shows the resistance of the person and footwear. This simplifies to: $R_{pf}=\frac{\mathcal{E}}{I}-R$ We plug in the known values to obtain: $R_{pf}=\frac{50.0V}{3.7\times 10^{-6}A}-10^6\Omega$ $R{pf}=12.5\times 10^6\Omega$ $R_{pf}=1.25\times 10^7\Omega$
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