Answer
a) $Q=1.6nC$
(b) As Q is inversely proportional to separation d, so the answer to part(a) will decrease if the separation is increased.
c) $Q=7.8\times 10^{-10}C$
Work Step by Step
(a) We know that
$Q=CV$
$Q=\frac{\epsilon_{\circ}AV}{d}$
We plug in the known values to obtain:
$Q=\frac{8.85\times 10^{-12}(0.0066)(12)}{0.45\times 10^{-3}}$
$Q=1.6nC$
(b) As Q is inversely proportional to separation d, so the answer to part(a) will decrease if the separation is increased.
(c) We know that
$Q=CV$
$Q=\frac{\epsilon_{\circ}AV}{d}$
We plug in the known values to obtain:
$Q=\frac{8.85\times 10^{-12}(0.0066)(12)}{0.90\times 10^{-3}}$
$Q=7.8\times 10^{-10}C$
