Answer
$1.34cm$
Work Step by Step
As $U=\frac{Kq_1q_2}{r}$
This can be rearranged as:
$r=\frac{Kq_1q_2}{U}$
We plug in the known values to obtain:
$r=\frac{(8.99\times 10^9)(7.22\times 10^{-6})(-2.61\times 10^{-6})}{-126}$
$r=0.0134m=1.34cm$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 20 - Electric Potential and Electric Potential Energy - Problems and Conceptual Exercises - Page 718: 29
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