Answer
(a) greater than
(b) $3.09\times 10^6m/s $
Work Step by Step
(a) We know that $ v=e\sqrt{\frac{K}{mr}}$. This equation shows that the speed is directly proportional to the charge. Thus, when the charge is doubled then the speed will also be doubled.
(b) As $ v=\sqrt{\frac{2K}{m_e r}}$
We plug in the known values to obtain:
$ v=(1.6\times 10^{-19}C)\sqrt{\frac{2(8.99\times 10^9N.m^2/C^2)}{(9.11\times 10^{-31}Kg)(5.29\times 10^{-11}m)}}$
$ v=3.09\times 10^6m/s $
