Answer
$-6.85^{\circ}C$
Work Step by Step
We can find the required temperature as follows:
$rate=\frac{227mmHg-0}{100-(-273.15^{\circ}C)}=0.60833mmHg/C^{\circ}$
We know that
$rate=\frac{P-P_{\circ}}{T-T_{\circ}}$
This can be rearranged as:
$T=T_{\circ}+\frac{P-P_{\circ}}{rate}$
We plug in the known values to obtain:
$T=100+\frac{162-227}{0.60833}=-6.85^{\circ}C$
