Answer
(a) $1.42KPa$
(b) $45KN$
Work Step by Step
As $P_2+\frac{1}{2}\rho v_2^2=P_1+\frac{1}{2}\rho v_1^2$
This simplifies to:
$P_2-P_1=\frac{1}{2}\rho(v_1^2-v_2^2)$
We plug in the known values to obtain:
$P_2-P_1=\frac{1}{2}(1.29)((115)^2-(1105)^2)=1.42KPa$
(b) We can find the net upward force as follows:
$\Delta F=\Delta PA$
We plug in the known values to obtain:
$\Delta F=(1.42\times 10^3)(32)=45KN$
