Answer
No, the ring is not solid gold.
Work Step by Step
To check the ring is solid gold,we will find the density of ring
$\rho=\frac{m}{V}$
We plug in the known values to obtain:
$\rho=\frac{0.014}{0.0022}$
$\rho=6.4\frac{g}{cm^3}$
We know that the density of the gold is $\rho_{gold}=19.3\frac{g}{cm^3}$, hence the ring is not solid gold.