Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 15 - Fluids - Problems and Conceptual Exercises - Page 530: 3

Answer

No, the ring is not solid gold.

Work Step by Step

To check the ring is solid gold,we will find the density of ring $\rho=\frac{m}{V}$ We plug in the known values to obtain: $\rho=\frac{0.014}{0.0022}$ $\rho=6.4\frac{g}{cm^3}$ We know that the density of the gold is $\rho_{gold}=19.3\frac{g}{cm^3}$, hence the ring is not solid gold.
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