Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 14 - Waves and Sound - Problems and Conceptual Exercises - Page 494: 61

Answer

$1.2KHz$

Work Step by Step

We can find the lowest frequency as follows: $d=\sqrt{(0.85)^2+(1.1)^2}=1.39m$ The wavelength is given as $\lambda=\Delta d=1.39-1.1=0.29m$ Now we can find the frequency $f=\frac{v}{\lambda}$ We plug in the known values to obtain: $f=\frac{343}{0.290}=1.2KHz$
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