Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 13 - Oscillations About Equilibrium - Problems and Conceptual Exercises - Page 448: 61

Answer

$2.4s$

Work Step by Step

We know that $\frac{T}{4}=\frac{\pi}{2}\sqrt{\frac{L}{g}}$ We plug in the known values to obtain: $\frac{T}{4}=\frac{\pi}{2}\sqrt{\frac{75ft}{9.81\frac{m}{s^2}}(\frac{0.305m}{ft})}$ $\frac{T}{4}=2.4s$
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