Answer
$(C) 1.1\times 10^{14}Kg$
Work Step by Step
We know that
$M_C=\frac{gR^2}{G}$
We plug in the known values to obtain:
$M_C=\frac{(9.8\times 10^{-4})(2700)^2}{6.67\times 10^{-11}}$
$M_C=1.1\times 10^{14}Kg$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 12 - Gravity - Problems and Conceptual Exercises - Page 414: 97
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