Answer
$g_T=1.36\frac{m}{s^2}$
Work Step by Step
We know that
$g_T=\frac{GM_T}{R_T^2}$
We plug in the known values to obtain:
$g_T=6.67\times 10^{-11}\times \frac{1.35\times 10^{23}}{(2.57\times 10^6)^2}$
$g_T=1.36\frac{m}{s^2}$
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