Answer
$a_{cp}=0.29\frac{m}{s^2}$ directed downward
$a_1=-2.1\frac{m}{s^2}$ directed towards left
Work Step by Step
We know that
$a_{cp}=r\omega^2$
We plug in the known values to obtain:
$a_{cp}=(9.5)(\frac{2\pi}{36})^2$
$a_{cp}=0.29\frac{m}{s^2}$ directed downward
As we know:
$a_1=r\alpha$
We plug in the known values to obtain:
$a_1=(9.5)(-0.22)=-2.1\frac{m}{s^2}$ directed towards left
