Answer
The closest he can get to the edge is .282 meters
Work Step by Step
Let x be the distance from the edge of the table to the person.
We sum the torques about the leg closest to the edge;
$(+ \circlearrowleft) \sum \tau =0$
$24kg*9.8m/s^2*.60m-66kg*9.8m/s^2(.5m-x)=0$
$24kg*9.8m/s^2*.60m-66kg*9.8m/s^2*.5m+x*66kg*9.8m/s^2=0$
$x=\frac{-24kg*9.8m/s^2*.60m+66kg*9.8m/s^2*.5m}{66kg*9.8m/s^2} $
$x\approx.282m $
