Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - Problems - Page 226: 70

Answer

See work below.

Work Step by Step

The angular velocity $\omega$ is the same for the rod and the small masses. To find the angular momentum, find the moment of inertia and multiply by the angular velocity. $$L=I \omega$$ $$L=(\frac{1}{12}M\mathcal{l}^2+2m(\frac{\mathcal{l}}{2})^2) \omega$$
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