Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 8 - Rotational Motion - Problems - Page 224: 39

Answer

(a) $I = 7.0~kg\cdot m^2$ (b) $I = 0.70~kg\cdot m^2$ (c) It would be harder to accelerate this array about the y axis because the moment of inertia about the y axis is larger.

Work Step by Step

(a) We can calculate the moment of inertia about the y axis. $I = (2.2~kg)(0.50~m)^2 + (2.2~kg)(1.00~m)^2 + (3.4~kg)(0.50~m)^2 + (3.4~kg)(1.00~m)^2$ $I = 7.0~kg\cdot m^2$ (b) We can calculate the moment of inertia about the x axis. $I = (2.2~kg)(0.25~m)^2 + (2.2~kg)(0.25~m)^2 + (3.4~kg)(0.25~m)^2 + (3.4~kg)(0.25~m)^2$ $I = (11.2~kg)(0.25~m)^2$ $I = 0.70~kg\cdot m^2$ (c) It would be harder to accelerate this array about the y axis because the moment of inertia about the y axis is larger.
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