Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 5 - Circular Motion; Gravitation - General Problems: 73


The minimum speed is 9.2 m/s.

Work Step by Step

If the centripetal acceleration is at least equal to $g$, then the people on the ride will not fall out. Therefore: $\frac{v^2}{r} = g$ $v = \sqrt{gr} = \sqrt{(9.80 ~m/s^2)(8.6~m)}$ $v = 9.2 ~m/s$ The minimum speed is 9.2 m/s.
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