Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 32 - Elementary Particles - Problems - Page 944: 9

Answer

0.9 MeV/revolution.

Work Step by Step

We assume that the speed of the protons is c. Calculate the period T, the time for one revolution. $$T=\frac{2\pi r}{c}$$ The number of revolutions N is the total time t divided by the period. $$N=\frac{t}{T}=\frac{ct}{2 \pi r}$$ The energy per revolution is the total energy gained divided by the number of revolutions. $$=\frac{\Delta E}{N}=\frac{(\Delta E) 2 \pi r }{ct}$$ $$=\frac{(1.0\times10^{12}eV-150\times10^{9}eV) 2 \pi (1000m) }{(3.00\times10^8 m/s)(20 s)}$$ $$=0.9 MeV/rev$$
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