Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 3 - Kinematics in Two Dimensions; Vectors - Problems: 12


a. B - 3A = (-131.37 units, -40.01 units). Magnitude 137.32, direction 16.93$^o$. b. 2A - 3B + C = (122.16 units, -86.59 units). Magnitude 150, direction 35.53$^o$.

Work Step by Step

Use equations 3.3a and 3.3b to find the x and y components. Vector B points at 124 degrees and vector C points at 270 degrees from the positive x-axis. Vector A = (38.85, 20.66) Vector B = (-14.82, 21.97) Vector C = (0, -31) a. Take the difference by subtracting multiples of the corresponding components. B - 3A = (-131.37 units, -40.01 units) Both components are negative, so the vector is in the 3rd quadrant. b. Again, take the difference by adding and subtracting multiples of the corresponding components. 2A - 3B + C = (122.16 units, -86.59 units)
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