## Physics: Principles with Applications (7th Edition)

Let x= 0 and y = 0 where the jumper starts, and let upward be the positive y direction. The vertical acceleration is $-9.8 \frac{m}{s^{2}}$, negative because it is directed downward. The time of flight is found from the constant horizontal velocity. t = 8.0 m/(9.1 m/s) = 0.88 s The time to fall from the highest height is half of that, or 0.44 s. Use equation 2.11b, with a starting vertical velocity of zero, to find a height of 0.95 m.