Answer
See answers.
Work Step by Step
a. Yes, the person in the picture with the camera is the photographer.
b. The mirror on the left side of the photograph is a converging/concave mirror. (A single diverging/convex mirror always produces an upright image.) The mirror in the middle is a regular flat mirror. The mirror on the right side of the photo is a diverging/convex mirror.
c. Consider the concave mirror on the left. Objects closer to a concave mirror than the focal point produce upright, enlarged images. Objects located between the focal point and the center of curvature produce enlarged images.
However, we see that the image is inverted and smaller than the object. This tells us that the photographer is at a distance greater than the center of curvature (which also means the distance is greater than the focal point).
Next, we consider the middle mirror. It is flat. The image is the same height as the object. The focal point and center of curvature are at infinity, so the person is closer than both of those quantities.
Finally, we consider the convex mirror on the right. The image is upright and about 1/2 the size of the image in the flat mirror, so we estimate m = +0.5. We can then solve the magnification equation for $d_i=-0.5d_o$. Plugging this into the mirror equation tells us $d_o=-f$. The photographer is standing at a distance from the mirror approximately equal to the magnitude of the focal length, halfway between the center of curvature and the mirror.
