Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - General Problems - Page 677: 79

Answer

12 cm

Work Step by Step

The magnification is -0.5. Use the magnification to find the image distance. It is real so it is a positive number. $$m=-0.5 = -\frac{d_i}{d_o}= -\frac{d_i}{18cm}$$ $$d_i=9.0cm$$ Use the mirror equation, 23–2. $$\frac{1}{d_o}+\frac{1}{d_i}=\frac{1}{f}$$ Solve for the focal length. $$f=\frac{d_od_i}{d_o+d_i}$$ $$=\frac{(18cm)(9.0cm)}{18cm+9.0cm}=6.0cm$$ The radius is twice the focal length, so r = 12 cm.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.