Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 23 - Light: Geometric Optics - General Problems - Page 676: 74

Answer

$f=20.0cm$

Work Step by Step

$d_{o1}=60.0cm$ $d_{o2}=40.0cm$ $d_{i2}-d_{i1}=10.0cm$ $d_{i}=\frac{fd_o}{d_o-f}$ $d_{i1}=\frac{fd_{o1}}{d_{o1}-f}=\frac{f(60.0cm)}{(60.0cm)-f}$ $d_{i2}=\frac{fd_{o2}}{d_{o2}-f}=\frac{f(40.0cm)}{(40.0cm)-f}$ $\frac{f(40.0cm)}{(40.0cm)-f}-\frac{f(60.0cm)}{(60.0cm)-f}=10.0cm$ $f=20.0cm$
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