Answer
a. No
b. 0.56 m/s
Work Step by Step
a. The sign of the ions won’t change the magnitude of the emf but as seen in Figure 20-21, will determine its polarity, i.e., which side of the artery is at a lower voltage.
b. See page 569. The ion flow velocity is the drift velocity, v, in the Hall effect equation.
$$V_{Hall}=vBd$$
$$v=\frac{V_{Hall}}{Bd}=\frac{0.13\times10^{-3}V}{(0.070T)(0.0033m)}=0.56m/s$$
