Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 2 - Describing Motion: Kinematics in One Dimension - Problems - Page 45: 41

Answer

The initial speed is 17 m/s and the maximum height is 14 meters.

Work Step by Step

The time to reach maximum height is 1.7 seconds. The velocity v at maximum height is v = 0 m/s. Therefore, $v = v_0 + at$ $v_0 = v - at = 0 - (-9.80)\times(1.7) = 16.66\approx17 ~m/s$ $y = v_0t + \frac{1}{2}at^2 = 16.66\times1.7 + \frac{1}{2}(-9.80)(1.7)^2$ $y = 14.16\approx14 ~meters$ The maximum height is 14 meters.
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