Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 2 - Describing Motion: Kinematics in One Dimension - General Problems - Page 48: 81

Answer

The time to fall from 3200 meters to 450 meters is 24 seconds. The speed at 450 meters would be 235 m/s.

Work Step by Step

We will first rearrange the following to find $t$: $y = \frac{1}{2}at^2$ $t = \sqrt{\frac{2y}{a}} = \sqrt{\frac{(2)(2750)}{9.80}} = 24 ~s$ Next, we use the following equation to find the speed: $v = v_0 + at = 0 + (9.8)(24) = 235 ~m/s$ The time to fall from 3200 meters to 450 meters is 24 seconds. The speed at 450 meters would be 235 m/s.
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