## Physics: Principles with Applications (7th Edition)

On Earth: $y_{e} = \frac{v^2-v_0^2}{2g} = \frac{-v_0^2}{2\times(-9.80)} = \frac{v_0^2}{2\times9.80}$ On the moon: $y_{m} = \frac{v^2-v_0^2}{2(g/6)} = 6\times\frac{-v_0^2}{2\times(-9.80)} = 6\times\frac{v_0^2}{2\times9.80} = 6\times y_{e}$ Therefore, the object will go 6 times higher on the moon.