Answer
7.4 ms.
Work Step by Step
The current in a circuit that is charging a capacitor is given by equation 19–7d. In this problem, we must use the equivalent series resistance and the equivalent series capacitance.
$$I=\frac{\epsilon}{R_{eq}}e^{-t/R_{eq}C_{eq}}$$
$$t=-R_{eq}C_{eq}ln(\frac{IR_{eq}}{\epsilon})$$
$$t=-(R_1+R_2)(\frac{C_1C_2}{C_1+C_2})ln(\frac{I(R_1+R_2)}{16.0V})$$
Substitute the numbers given to obtain a time t of $7.4\times10^{-3}s$.
