Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 19 - DC Circuits - Problems - Page 554: 51

Answer

a) $C_{eq}=\frac{3}{5}C$ b) $Q_1=Q_2=\frac{1}{5}CV$ $Q_3=\frac{2}{5}CV$ $Q_4=\frac{3}{5}VC$ $V_1=V_2=\frac{1}{5}V$ $V_3=\frac{2}{5}V$ $V_4=\frac{3}{5}V$

Work Step by Step

a) $C_{1,2}=\frac{1}{\frac{1}{C_1}+\frac{1}{C_2}}$ $C_{1,2,3}=\frac{1}{\frac{1}{C_1}+\frac{1}{C_2}}+C_3$ $C_{eq}=\frac{1}{\frac{1}{C_4}+\frac{1}{\frac{1}{\frac{1}{C_1}+\frac{1}{C_2}}+C_3}}=\frac{3}{5}C$ b) $V=V_4=V_3=V_1+V_2$ $Q_1=Q_2$ $Q_1+Q_3=Q_4$ $Q_4=\frac{3}{5}VC$ $V_4=\frac{3}{5}V$ $V_{1,2,3}=\frac{2}{5}V=V_3$ $Q_3=\frac{2}{5}CV$ $Q_1=Q_2=C_{1,2}V_{1,2}=(\frac{1}{2}C)(\frac{2}{5}V)=\frac{1}{5}CV$ $V_1=\frac{Q_1}{C_1}=\frac{1}{5}V=V_2$
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