Answer
a) $V_1=12.0V$
$V_2=9.0V$
$V_3=21.0V$
b) $Q_1=36\mu C$
$V_2=36\mu C$
$V_3=77.9\mu C$
Work Step by Step
$C_{eq}=\frac{1}{\frac{1}{C_1}+\frac{1}{C_2}}+C_3=3.71\mu F$
$Q=C_{eq}V=(3.71\mu F)(21.0V)=77.9\mu C$
$V_3=21.0V$
$Q_3=C_3V_3=(2.00\mu F)(21.0V)=42.0\mu C$
$V_1+V_2=V_3$
$Q_1=Q_2=\frac{Q-Q_3}{2}=36\mu C$
$V_1=\frac{Q_1}{C_1}=\frac{36\mu C}{3.00\mu F}=12.0V$
$V_2=V_3-V_1=9.0V$
a) $V_1=12.0V$
$V_2=9.0V$
$V_3=21.0V$
b) $Q_1=36\mu C$
$V_2=36\mu C$
$V_3=77.9\mu C$
