Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 18 - Electric Currents - Search and Learn - Page 525: 5

Answer

1550 watts.

Work Step by Step

The heater heats 130 cubic meters of air per hour from $5^{\circ}$ to $22^{\circ}$. Use equation 14–2 to calculate the energy needed to heat the air. $$Q=mc\Delta T$$ $$\frac{Q}{t}=\frac{m}{t}c \Delta T=\frac{130m^3}{3600s}\frac{1.29kg}{m^3}\frac{0.17kcal}{kg \cdot C^{\circ}}(17C^{\circ})=0.1346kcal/s$$ The heater also replaces the heat that is being lost (850 kcal/h, or 0.2361 kcal/s). Calculate the total required power. $$(0.1346kcal/s+0.2361 kcal/s)\frac{4186J}{kcal}\approx 1550W$$
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