Answer
See answers.
Work Step by Step
a.
$$C=\frac{\epsilon_o A}{d}=\frac{8.85\times10^{-12}(110\times10^6 m^2)}{1500m}\approx 0.65\mu F$$
b.
$$Q=CV=(6.49\times10^{-7}F)(3.5\times10^7V)\approx 23C$$
c.
$$PE=\frac{1}{2}CV=\frac{1}{2}(22.715C) (3.5\times10^7V)=4.0\times10^8J$$
