Answer
The flux will be the same for the cubical surface as it was for the spherical surface.
Work Step by Step
The electric flux $\Phi_{E}$ only depends on the charge enclosed by the Gaussian surface. The shape of the surface doesn’t matter.
Physics: Principles with Applications (7th Edition)
by Giancoli, Douglas C.
Published by
Pearson
ISBN 10:
0-32162-592-7
ISBN 13:
978-0-32162-592-2
Chapter 16 - Electric Charge and Electric Field - Questions - Page 467: 22
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
