Answer
a) $\Delta x=8.52\times10^{-3}m$
b) $t=6.41\times10^{-9}s$
Work Step by Step
a) $F=Eq=(9.45\times10^3N/C)(-1.60\times10^{-19}C)=$$-1.51\times10^{-15}N$
$a=\frac{F}{m}=\frac{-1.51\times10^{-15}N}{9.11\times10^{-31}kg}=-1.66\times10^{15}m/s^2$
$\Delta x=\frac{v_f^2-v_i^2}{2a}=\frac{(0m/s)^2-(5.32\times10^6m/s)^2}{2(-1.66\times10^{15}m/s^2)}=8.52\times10^{-3}m$
b) $0=v_it+\frac{1}{2}at^2=$$(5.32\times10^6m/s)t+\frac{1}{2}(-1.66\times10^{15}m/s^2)t^2$
$t=6.41\times10^{-9}s$
