Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 14 - Heat - Problems - Page 410: 39

Answer

It takes 21 hours for the ice to melt.

Work Step by Step

We can find the rate of energy absorption of the block of ice; $\frac{Q}{t} = (1000~W/m^2)\epsilon ~A~cos(\theta)$ $\frac{Q}{t} = (1000~W/m^2)(0.050)(1.0~m^2)~cos(35^{\circ})$ $\frac{Q}{t} = 40.96~W$ We can find the mass of the block of ice; $m = \rho~V$ $m = (917~kg/m^3)(1.0~m^2)(0.010~m)$ $m = 9.17~kg$ We can find the energy required to melt the ice: $Q = m~L$ $Q = (9.17~kg)(3.33\times 10^5~J/kg)$ $Q = 3.05\times 10^6~J$ We can find the time it takes to melt the ice: $t = \frac{Q}{P}$ $t = \frac{3.05\times 10^6~J}{40.96~W}$ $t = 7.45\times 10^4~s$ We can convert this time to units of hours: $t = (7.45\times 10^4~s)(\frac{1~hr}{3600~s})$ $t = 21~hr$ It takes 21 hours for the ice to melt.
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