Answer
$T=181^oC$
Work Step by Step
$PV=nRT$
$\frac{P_i}{T_i}=\frac{P_o}{T_o}$
$P_i=\frac{P_oT_i}{T_o}$
$\sum F=(P_i-P_o)A$
$\sum F=(\frac{P_oT_i}{T_o}-P_o)A$
$T_i=\frac{FT_o}{AP_o}+T_o=\frac{(10.0N)(18^oC+273)}{(\pi(0.0075m)^2)(1.013\times10^5)}+(18^oC+273)=454K$
$454K-273=181^oC$