Physics: Principles with Applications (7th Edition)

Published by Pearson
ISBN 10: 0-32162-592-7
ISBN 13: 978-0-32162-592-2

Chapter 13 - Temperature and Kinetic Theory - Problems - Page 385: 2

Answer

$3.2\times10^{22} atoms$

Work Step by Step

$\frac{3.4 g Cu}{1}\times\frac{1 mol Cu}{63.546 g Cu}\times\frac{6.023\times10^{23} atoms}{1 mol}$ $= 3.2\times10^{22} atoms$
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